25p^2+10p+1=0

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Solution for 25p^2+10p+1=0 equation: 



25p^2+10p+1=0

a = 25; b = 10; c = +1;
Δ = b2-4ac
Δ = 102-4·25·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{-10}{50}=-1/5$

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